Whether you’re buying a new or existing home or want to best protect the property you currently own, it’s important to have sufficient homeowners insurance coverage in place. But these policies can get expensive, depending on your coverage inclusions and level.

Safeco provides the cheapest homeowners insurance with an average cost of $1,046 per year.

To help you save money on homeowners insurance, we’ve researched the industry and can suggest three particular insurers with the most affordable coverage on average in Wyomin. Read on for our recommendations and tips for shopping around and saving money on homeowners insurance.

Key Takeaways

  • At $87 per month, Safeco offers the cheapest homeowners insurance in Wyomin with $300,000 dwelling coverage, $300,000 liability protection and $1,000 deductible.
  • After Safeco, Amco and State Farm offer cheaper homeowners insurance in Wyomin.
  • Amongst all the large cities surveyed by Insure.com in Wyomin, the city with zip code 82801 offers the cheapest homeowners insurance at $134 per month or $1,608 annually.

Cheap homeowners insurance companies in Wyoming

Safeco, Amco and State Farm have the lowest average home insurance rates with $300,000 dwelling and $300,000 liability coverage with a $1,000 deductible.

Here are the average Wyomin homeowners insurance rates by company. You may wonder: How much is homeowners insurance a month in Wyomin? We included those averages, too:

CompanyAverage annual premiumAverage monthly premium
Safeco$1,046$87
Amco$1,288$107
State Farm$1,707$142
USAA$2,567$214
Foremost$2,748$229
Allstate$4,026$336

Compare cheap homeowners insurance in Wyoming by ratings

It’s always wise to shop around and compare prices before you buy your home insurance. There are many factors that go into deciding the best homeowners insurance company. We have compared the insurers in Wyomin using their J.D. Power score and AM Best rating and put together a list of the cheap homeowners insurance companies.

CompanyJ.D. Power scoreAM Best rating
USAA882A++
State Farm835A++
Allstate829A+
Safeco810A

How much is home insurance in Wyoming

The average Wyomin homeowners insurance is $2,083 for a policy with $300,000 dwelling coverage and $300,000 liability with a $1,000 deductible. Experts recommend at least $300,000 liability coverage to protect your home against lawsuits. The average Wyomin home insurance costs are $222 less than the national average.

Actual home insurance costs vary depending on multiple metrics, including location, claims history and discounts, such as auto and home bundling.

For instance, home insurance premiums are partially based on the home’s claims history (even from before you bought the property) and your neighbor’s claims history.

Homeowners insurance companies decide upon rates based on risks. If your neighborhood has seen many claims over the past few years, you can expect to pay higher home insurance rates than an area with few to no claims. Your credit score can also play a role in your home insurance costs.

Average annual premiumAverage monthly premium
$2,083$174

Cheapest homeowners insurance in Wyoming by ZIP code

Not every city in Wyomin have the same home insurance costs. The price of homeowners insurance depends on a lot of different factors and one of them is your zip code. The least expensive zip code for home insurance in Wyomin is 82801 with an average annual premium of $1,608 per year.

Find below the homeowners insurance annual and monthly rate for your zip code.

ZIP codeAverage annual premiumAverage monthly premium
82801$1,608$134
83113$1,682$140
82901$1,694$141
83101$1,699$142
82930$1,704$142
83120$1,721$143
82944$1,725$144
83001$1,726$144
82941$1,729$144
83110$1,746$146
83012$1,748$146
82833$1,756$146
83118$1,768$147
82514$1,775$148
83011$1,783$149

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